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-1=0.5x^2+2.35x
We move all terms to the left:
-1-(0.5x^2+2.35x)=0
We get rid of parentheses
-0.5x^2-2.35x-1=0
a = -0.5; b = -2.35; c = -1;
Δ = b2-4ac
Δ = -2.352-4·(-0.5)·(-1)
Δ = 3.5225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.35)-\sqrt{3.5225}}{2*-0.5}=\frac{2.35-\sqrt{3.5225}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.35)+\sqrt{3.5225}}{2*-0.5}=\frac{2.35+\sqrt{3.5225}}{-1} $
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